kuruminnsita

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Friday, January 09, 2026

「by for e」

 by for e


​e^(iπ) + 1 = 0

​e^(iπ) = -1

​e^(iπ) = e^(iπ)

​1 = -(e^(iπ))

​-1 = e^(iπ)

​0 = (e^(iπ)) + 1

​1 = ...

​Q.E.D.

​:。


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